[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Can't save a node tree in a variable.
And can you say me why in the following xsl the processor doesn't step
into this template:
<xsl:template match="/" mode="main"> <xsl:apply-templates select="$sorted" mode="main"/> </xsl:template> The hole xsl: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"> <xsl:output media-type="xml"/> <xsl:variable name="sorted"> <xsl:apply-templates mode="copy" select="data/item"/> </xsl:variable> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"> <xsl:sort select="@sector"/> <xsl:sort select="@subsector"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template match="/" mode="main"> <xsl:apply-templates select="$sorted" mode="main"/> </xsl:template> <xsl:template match="item" mode="main"> <xsl:for-each select="item"> <xsl:value-of select="."/> </xsl:for-each> </xsl:template> </xsl:stylesheet> Mon, 25 Jul 2005 16:18:45 +0200, Geert Josten <Geert.Josten@xxxxxxxxxxx> ohq`k(`): You will need to use a node-set extension function in XSLT 1.0... --- GSM.By.COM - hmrepmer-l`c`ghm qnrnb{u reketnmnb qr`md`pr` GSM, `jqeqqs`pnb h g`ow`qrei j mhl. Xhpnjhi b{anp, p`gslm{e vem{, noep`rhbm` dnqr`bj`. Pelnmr reketnmnb. http://www.gsm.by.com
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