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Re: Identify last node in nested nodeset with same nam

Subject: Re: Identify last node in nested nodeset with same name
From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx>
Date: Fri, 24 Jun 2005 01:04:38 -0700 (PDT)
count child tags in xml
Hi Mat,
  Please try this XSL .. It seems to solve the problem
...

<?xml version="1.0"?> 
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
 
<xsl:output method="xml" indent="yes" /> 
 
<xsl:template match="node() | @*">  
  <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
  </xsl:copy>
</xsl:template>
 
<xsl:template match="root">
  <ul>
    <xsl:apply-templates />
  </ul>  
</xsl:template>
 
<xsl:template match="menu">
  <xsl:choose>
    <xsl:when test="child::*">
      <li><xsl:value-of select="@name" /></li>
        <ul>
          <xsl:apply-templates />
        </ul>  
      </li>
    </xsl:when>
    <xsl:otherwise>
      <li>
        <xsl:value-of select="@name" />
      </li>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>
 
</xsl:stylesheet>

Regards,
Mukul

--- Mat Bergman <matbergman@xxxxxxxxx> wrote:

> I am working with XML data that shares the same
> element name for each node set, for example:
> 
> <menu name="link1"/>
> <menu name="link2">
>      <menu name="link2a"/>
>      <menu name="link2b"/>
> </menu>
> 
> My XSL stylesheet transforms this into an HTML
> unordered list, like this:
> <ul>
> <li>link1</li>
> <li>link2
>      <ul>
>      <li>link2a</li>
>      <li>link2b</li>
>      </ul>
> </li>
> </ul>
> 
> I can't figure out how to identify the last
> second-tier node (in this example "link2b") so that
> the stylesheet can write the closing </ul> tag for
> the
> nested list. I thought I would reference it with
> something like <xsl:if test="/menu/menu[last()]">,
> but
> my XPath must be incorrect because it fails.
> 
> I am currently writing the opening <ul> and closing
> </li> tags for the nested list with this:
> 
> <xsl:template match="menu">
> <xsl:if test="count(menu)>0">
> <xsl:text>&lt;ul&gt;</xsl:text>
> </xsl:if>
> 
> <xsl:if test="count(menu)=0">
> <xsl:text>&lt;/li&gt;</xsl:text>
> </xsl:if>
> </xsl:template>
> 
> If I only knew how to identify the last node in
> /menu/menu, I could easily write the closing tag.
> 
> Thanks,
> 
> -Mat
> 
> 
> 
> 
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