[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Can a named template return a node list?
Sorry in advance for my terminology. Is it possible for a named
template to return a node list? Here is some simplified XML with which
I have been experimenting:
<root> <node1 attr="node1attrval"> <node1a>node1atext</node1a> </node1> <node2 attr="node2attrval"> <node2a>node2atext</node2a> </node2> </root> And the XSL I have been trying: <xsl:template match="*"> <xsl:variable name="somenode"> <xsl:call-template name="sometemplate" /> </xsl:variable> <xsl:value-of select="$somenode/@attr" /> </xsl:template> <xsl:template name="sometemplate"> <xsl:copy-of select="/root/node1" /> </xsl:template> The reference to $somenode/@attr gives an error. I think the problem is with copy-of - I want it to return a reference to a node, but it seems to return the value of the node. Is there some other function or approach I should try? I have tried value-of and copy, and I am hoping to stay away from XSL extensions if possible. I cannot use XSL 2. Thanks, -John
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