[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XSL siblings
Yes, you're having problem understanding context. At least this time you've shown us an input document and a stylesheet. But you haven't given us any clue what output you want to produce. However, it's hard to imagine that <xsl:for-each select="SAM"> <xsl:for-each select="//SAM[A/AID = 'xxx']"> is doing anything useful ("for each SAM, process all the SAMs with an A/AID equal to 'xxx') Here: <xsl:for-each select="C"> doesnt work since im looping a sibling node outside of it, you seem to have grasped the essence of the problem, which is that relative path expressions only work if you get the context right. You probably want select="../C". Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: -= jay =- [mailto:deepsweech@xxxxxxxxx] > Sent: 28 June 2005 09:24 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: XSL siblings > > i have this problem again but now there's 3 siblings! > > example > <SAM> > <A> > <AID>xxx</AID> > </A> > <B> > <BID>yyy</BID> > </B> > <C> > <CID>zzz</CID> > </C> > </SAM> > <SAM> ..... and so on > > nows here is my current code: > <xsl:for-each select="SAM"> > <xsl:for-each select="//SAM[A/AID = 'xxx']"> > <xsl:for-each select="B"> > <xsl:if test="BID='yyy' or BID='something'"> > <xsl:value-of select="BID"> > -- here is the my problem, i would like to display all CID under > filtered SAM. --- > <xsl:for-each select="C"> doesnt work since im > looping a sibling node outside of it, > > thanks, > *-::jay::-*
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