[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XSL distinct group by date
Mindy,
At 03:12 PM 5/1/2005, you wrote: Now if I use the XSLT in the above link (http://sources.redhat.com/ml/xsl-list/2000-07/msg00458.html), it does return the distinct customer name values, but it also writes out the value of the nodes outside the /projects level, yielding: Customer 1Customer 2 A Paper Title This is undoubtedly happening because these nodes are being selected by default and matched by the built-in templates, so their contents are being copied to the result tree and written out. (The Jeni-code in the post cited did not include any of the templates that would handle other structures in a real case; if you leave those out, you'll get the default behavior, which is as you describe.) The solution is either to arrange not to select the nodes you don't want, or to assure that when they are selected and matched, nothing gets done with them. (The latter is commonly done by matching them with empty templates.) Terms to research: built-in templates; XSLT processing model; semantics of xsl:apply-templates and its select attribute. Short version: try using a template like this <xsl:template match="company"> <xsl:apply-templates select="projects"/> </xsl:template> to replace the built-in template, which would look like this: <xsl:template match="company"> <xsl:apply-templates select="child::node()"/> </xsl:template> Cheers, Wendell
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