RE: xsl:include problems

My mistake - now I see.  You're right, I wasn't declaring the xsl: namespace
prefix in "replace_string.xsl".

Here is what I have now in "replace_string.xsl":

<?xml version="1.0" encoding="UTF-8" ?>
<stylesheet
	version="1.0"
	xmlns="http://www.w3.org/1999/XSL/Transform"
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

I just put in the last "xmlns:xsl" line.  But it still doesn't work - I'm
still getting a blank page.

Here is the top of my main style sheet:
*---------------------------------
<?xml version='1.0'?>
<xsl:stylesheet
	version="1.0"
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
	xmlns:msxsl="urn:schemas-microsoft-com:xslt">

<xsl:include href="replace_string.xsl" />
*---------------------------------

Is there something more I need to do?

>>> mike@xxxxxxxxxxxx 5/31/2005 12:42 PM >>>
> We're using MSXML4 and I'm trying to get xsl:include to work
> but I'm having trouble.  I created file "replace_string.xsl"
> that contains this:
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <stylesheet version="1.0"
> xmlns="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template name="replace-string">


You haven't declared the xsl: namespace prefix.

(MSXML's error reporting is not always brilliant...)

Michael Kay
http://www.saxonica.com/