[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: tansforming an XML into another XML help needed !
Here's another approach: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" encoding="UTF-8" /> <xsl:strip-space elements="*" /> <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="record"> <record name="{@name}"> <xsl:apply-templates /> </record> </xsl:template> <xsl:template match="item[@name='Title_EN']"> <item name="english"> <value> <item name="Title"> <value><xsl:value-of select="value" /></value> </item> <xsl:if test="following-sibling::item[@name='Paragraph']/value/item[@name='SubParagraph_EN']"> <item name="Paragraph"> <value> <xsl:apply-templates select="following-sibling::item[@name='Paragraph']/value/item[@name='SubParagraph_EN']" /> </value> </item> </xsl:if> </value> </item> </xsl:template> <xsl:template match="item[@name='Title_FR']"> <item name="french"> <value> <item name="Title"> <value><xsl:value-of select="value" /></value> </item> </value> <xsl:if test="following-sibling::item[@name='Paragraph']/value/item[@name='SubParagraph_FR']"> <item name="Paragraph"> <value> <xsl:apply-templates select="following-sibling::item[@name='Paragraph']/value/item[@name='SubParagraph_FR']" /> </value> </item> </xsl:if> </item> </xsl:template> <xsl:template match="item"> <item name="common"> <value> <xsl:copy-of select="." /> </value> </item> </xsl:template> <xsl:template match="item[@name='SubParagraph_EN'] | item[@name='SubParagraph_FR']"> <item name="SubParagraph"> <xsl:copy-of select="value" /> </item> </xsl:template> <xsl:template match="item[@name='Paragraph']" /> </xsl:stylesheet> -- Charles Knell cknell@xxxxxxxxxx - email
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