RE: Combining two node Sets into one

You can probably tell my inexperience with this because I probably opted to
take the most complex path possible.  I will give this a try on Monday and
see what I can come up with.  

Thanks again for the help,

Chris

-----Original Message-----
From: Wendell Piez [mailto:wapiez@xxxxxxxxxxxxxxxx] 
Sent: Friday, April 01, 2005 4:49 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Combining two node Sets into one


Chris,

At 04:24 PM 4/1/2005, you wrote:
>I have no way now to get the dates in order without calling some 
>ridiculous recursive template that sorts the nodes for me and prints 
>the appropriate one. Loop.. Print. which could result in a high number 
>of passes..

Why not sort them with the same instruction you'd use to sort them if 
converting them to an intermediate format?

<xsl:template match="/">
    <table>
      <xsl:apply-templates select="//Disbs | //Refunds">
        <xsl:sort select="DisbDetail/Ddate | RefDetail/Rdate"/>
      </xsl:apply-templates>
    </table>
</xsl:template>

<xsl:template match="Disbs | Refund">
   <tr class="{local-name()}">
     ... etc ...
   </tr>
</xsl:template>

... the 'class' attribute there gets the value "Disbs" or "Refund" -- i.e. 
the name of the matched element.

There are cases where complex sorting and grouping requirements push us 
into having to process temporary trees, but I haven't yet seen anything 
here that makes me think this is one of them.

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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