Re: Print number of chars depending upon int value

This reminds me of a submission to xsl-list in 2001:

"An efficient repeat() template (Was: RE: Re: RE: creating a string of
repeated charactors)"

     http://www.biglist.com/lists/xsl-list/archives/200107/msg01040.html


So, we have an example of efficient and scalable solution of this
problem for very big N.


Cheers,
Dimitre Novatchev.


On 4/22/05, Ranjan K. Baisak <ranjanbaisak@xxxxxxxxx> wrote:
> :D David, I am quite agree with you.
> This is an instance where I have mentioned keeping eye
> with other functions/constructs available in XSLT2.0
> I really did not count how many exact lines would be
> there :(
>
> -Ranjan
> --- David Carlisle <davidc@xxxxxxxxx> wrote:
> >
> > > Should not there be an alternative for any
> > function in
> > > xslt2.0 in xslt 1.0.
> >
> > No, of course not.
> > What would be the difference between (xslt1 + xslt1
> > versions of all
> > xslt2 features) and xslt2.
> >
> > This is not specific to xslt, for any language, if a
> > new feature is
> > added in a new version, it's not available in the
> > old one.
> >
> > > Otherwise it is required to write 100 lines of
> > code as
> > > mentioned by Eliot Harold.
> >
> >
> > In this case it's not 100's of lines. Unless your
> > padding needs to be
> > really long (ie nore characters than there are nodes
> > in your stylesheet)
> > then you can do
> >
> > <xsl:for-each
> > select="(document('')//node())[position() <=
> > $count]">.</xsl:for-each>
> >
> > if you want to do a fully general recursive loop
> > then something like
> >
> > <xsl:template name="x">
> >  <xsl:param name="n"/>
> >   <xsl:if test="$n!=0">.<xsl:call-template name="x">
> >      <xsl:with-param name="n" select="$n - 1"/>
> >      </xsl:call-template>
> >   </xsl:if>
> > </xsl:template>
> >
> > which is 7 lines, 3 of which are just closing open
> > elements so it's
> > really only 3 lines of code.
> >
> > David
> >
> >
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