Re: Add order of nodes

Joris wrote

   > <doc>
   > 	<fragment>...</fragment>
   > 	<fragment>...</fragment>
   > 	<fragment>...</fragment>
   > 	...
   > </doc>
   >
   > I need a <xsl:template match="fragment"> that produces this output:
   >
   > <doc>
   > 	<fragment pos="1">...</fragment>
   > 	<fragment pos="2">...</fragment>
   > 	<fragment pos="3">...</fragment>
   > 	...
   > </doc>	
   >
   > Can I use position() for that?
   Yes indeed.

   use this tremplate:

   <xsl:template match="fragment">
	   <xsl:copy>
		   <xsl:attribute name="pos"><xsl:value-of  
   select="position()"/></xsl:attribute>
		   <xsl:apply-templates select="node()|@*"/>
	   </xsl:copy>
   </xsl:template>


   (in conjunction with this template)
   <xsl:template match="node()|@*">
	   <xsl:copy>
		   <xsl:apply-templates select="node()|@*"/>
	   </xsl:copy>
   </xsl:template>


You should also add a template

<xsl:template match="doc">
 <doc>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates select="fragment"/>
 </doc>
</xsl:template>


to make sure that the current node list  when applying templates to
fragments does just consist of fragment elements so position()
goes 1 2 3  otherwise with the select="node()|@*" it would also include
white space text so the fragment elements would be in positions 2 4 6 
and if the doc element had any attributes the position of the fragment
nodes in the node set returned by "node()|@* would be increased
accordingly.

David

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