[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: HELP! The XSLT may be easy, but I could not figure
In 2.0, that's <xsl:for-each-group select="data" group-starting-with="data[ends-with(., 'A')]"> <group> <xsl:apply-templates select="current-group()"/> </group> </xsl:for-each> <xsl:template match="data"> <amount><xsl:value-of select="."/></amount> </xsl:template> Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: piming.kuo@xxxxxxxxxxxxx [mailto:piming.kuo@xxxxxxxxxxxxx] > Sent: 07 February 2005 14:39 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: HELP! The XSLT may be easy, but I could not > figure it out > > Can anyone help? Thanks in advance. > > I have the xml document like: > > <response> > <all> > <data>12345A</data> > <data>22345B</data> > <data>32345A</data> > <data>42345B</data> > <data>52345B</data> > <data>62345A</data> > <data>72345A</data> > <all> > </response> > > And like to transform it to another xml document. For all > <data> under the > <all>, Start a new group > with the <group> following with <amount> when the last > character of context > of the <data> is A; otherwise add the <amount> with the context when > the last character of the context of the <data> is "B". > > I had tried with for-each and following, but could not get > what I want. > > <response> > <group> > <amount>12345A</amount> > <amount>22345B</amount> > </group> > <group> > <amount>32345A</amount> > <amount>42345B</amount> > <amount>52345B</amount> > </group> > <group> > <amount>62345A</amount> > <amount>72345B</amount> > </group> > </response> > > Have a nice day! > > Piming Kuo
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