[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Adding element to xml snippet using xslt
Joris Gillis wrote:
Tempore 23:01:31, die 02/21/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Nishi Bhonsle <nishi.bhonsle@xxxxxxxxxx>: Hi: I tried the above select statement in the xslt, but it still yields an empty 'started' element in the output file. ie <xsl:element name="started"> <xsl:copy-of select="../abc:configuration/started/@status[. = 'true' ]"/> </xsl:element> If I create the 'drillOutDir' and the 'started' elements outside the 'server' elements template then I noticed that after applying the transformation, the resultant output does not contain them AT ALL. I tried the below, but neither worked. All the below templates result in NOT containing the 'drillOutDir' and 'started' nodes in the output file. <xsl:template match="abc:configuration/drillOutDir"> <xsl:element name="drillOutDir"> <xsl:value-of select="abc:configuration/drillOutDir"/> </xsl:element> </xsl:template> <xsl:template match="abc:configuration"> <xsl:element name="drillOutDir"> <xsl:value-of select="abc:configuration/drillOutDir"/> </xsl:element> </xsl:template> Can you suggest anything? Thanks.
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