RE: How to call extension function from xpath multiple

Hi,

  Got it. It should be z instead of a
	<xsl:template match="z"> instead of  <xsl:template match="a">

regards
Manpreet Singh

-----Original Message-----
From: Manpreet Singh
Sent: Tuesday, January 04, 2005 4:01 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: FW:  How to call extension function from xpath multiple
times?
Importance: High


Hi,

My Source xml:

<?xml version="1.0" encoding="UTF-8"?>
<z>
	<b13>123<a>ftp<c12>c12</c12></a></b13>
	<b2>456<a>ftp1<c1>c1</c1></a></b2>
</z>

  I am working with the following xsl:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dit="Tester">
	<xsl:template match="a">
		<xsl:apply-templates
select="*[dit:matchString('b_qstnmark_',local-name(.))]/a/*[dit:matchString('
c_qstnmark_',local-name(.))]"/>
	</xsl:template>
	<xsl:template
match="*[dit:matchString('b_qstnmark_',local-name(.))]/a/*[dit:matchString('c
_qstnmark_',local-name(.))]">
		<xsl:value-of select="concat(local-name(.), ' - ', .)"/>
	</xsl:template>
</xsl:stylesheet>

The java class for the extension function i call is as follows:

import java.util.StringTokenizer;

public class Tester {
	public static boolean matchString(String pattern, String elemName) {
		int index = pattern.lastIndexOf("/");

		if(index != -1) {
		pattern = pattern.substring(index + 1);
		}

		pattern = pattern.replaceAll("_asterix_", "\\\\w*");
		pattern = pattern.replaceAll("_qstnmark_", "\\\\w");

		return java.util.regex.Pattern.matches(pattern, elemName);
	}
}

My problem is that the xpath of apply-templates above does not work. My
template below never gets a call.

Any Help?

Regards
Manpreet Singh