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Re: Equivalence between XSL and XPath expression
Subject: Re: Equivalence between XSL and XPath expression
From: xptm <xptm@xxxxxxx>
Date: Sat, 11 Dec 2004 00:54:19 +0000
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So basically you're saying that the root element doesn't have the self::
axis, besides the obvious ancestor, parent and preceding. Is that so?
Michael Kay wrote:
How can the XPath return 0, if has a context node (.) and has
the self
axis in ancestor-or-self? This way it has to return at least 1!
I think you are assuming the context node is a menu element. There's no
reason to assume that. If the context node is the root (document) node (for
example) the XPath expression will return 0.
Michael Kay
http://www.saxonica.com/
Michael Kay wrote:
And the question is: Is this XPath expression
count(./ancestor-or-self::menu)+count(./preceding::menu)
equivalent to this XSL expression?
<xsl:variable name="position">
<xsl:number level='any' count="menu"/>
</xsl:variable>
Almost. xsl:number will never return 0, but the XPath
expression might. Take
a look at the XSLT 2.0 spec which defines xsl:number in
terms of equivalent
XPath expressions.
Michael Kay
http://www.saxonica.com/
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