Re: Re: [xslt transform & grouping] Using the Muenchia

<Documents>
	<Document chapter="1" title="title 1" href="file1.xml" filter="">
		<Article title="1.1" info="sub" filter="drink"/>
		<Article title="1.2" info="main" filter="food"/>
	</Document>
	<Document chapter="2" title="title 2" href="file2.xml" filter="drink">
		<Article title="2.1" info="sub" filter="drink"/>
		<Article title="2.2" info="main" filter="food"/>
	</Document>
</Documents>

From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: Re: [xslt transform & grouping] Using the Muenchian Method?
Date: Tue, 5 Oct 2004 16:06:51 +0100

> Use this XSLT to genterate new XML file by using specified XML input
> file:

clearly that will generate an error as it uses a kety that is not
defined, as I pointed out in the message that you quoted.
As such it will generate no output.

If you fix that then you will get no error

and if you fix     <xsl:param name="filter" select="food"></xsl:param>
to have 'food' then you will get the output that I also posted in that
message, assuming you have a conforming processor.

If you leave $filter with that value you'll just get an empty Documents
element as $filter would be an empty node set as previously explained.

David

________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________