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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Retrieving top section from a navigation tree
 I have a navigation tree and would like to find out which main navigation section I am located underneath when i have the unique id of the page I am viewing. Here's an example tree;
<xsl:variable name="ul">
<ul id="menu">
<li id="1">one</li>
<li id="2">two
<ul>
<li id="2-1">two-one</li>
<li id="2-2">two-two
<ul>
<li id="2-2-1">two-two-one</li>
</ul>
</li>
</ul>
</li>
<li id="3">three</li>
</ul>
</xsl:variable><xsl:variable name="id" select=="'2-2-1'" /> Say I am viewing the page "2-2-1", I would now like to write an xpath expression that retrieves the name (text element) of the containing top li element. In this case the name would be "two". I have tried to look at the problem from differen perspectives; - one is to find the top <li> elements and filter out any that does not contain an <li> element that matches the page $id - the other is to find the <li> element with the specific @id, and traverse outwards to find the containing top <li> element Sadly I do not understand how I would retrieve the name "two" using any of these methods. My failed xpath expression so far looks like this; exsl:node-set($ul)/ul[@id='menu']/li[//li/@id=$id]/text() Thank you for your help. Best regards, Mario Caprino _________________________________________________________________ MSN Messenger http://www.msn.no/computing/messenger Den raskeste veien mellom deg og dine venner 
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