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hi all,
I have a question related to the copy-of function in xslt 2.0: I would like to deep copy a piece of my source XML to a new XML file, without declaring all Namespaces of my source XML in my copied excerpt. I know, I can make use of the xsl:copy-of function with the copy-namespaces attribute set to 'no'. Then, my targetnamespace is indeed copied, and other Namespace declarations of my source XML document (such as the foo NS) are omitted. However, I still would like to keep the xmlns:xsi Namespace declaration in the copied excerpt (as this would make the latter self-contained). Does anyone knows how to do this? I provide an illustrative example below. Many thanks in advance chris
<foo:wrapper xmlns:foo="http://foo" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <!-- start excerpt to be copied --> <bar:excerpt xmlns:bar="http://bar" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" > <bar:subject>blablabla</bar:subject> <bar:subject>blablabla</bar:subject> <dc:author xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >blablabla</dc:author> </bar:excerpt> <!-- end excerpt to be copied --> </foo:wrapper> output XML: ---------- <bla:container xmlns:bla="http://bla" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <!-- start copied excerpt --> <bar:excerpt xmlns:bar="http://bar" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" > <bar:subject>blablabla</bar:subject> <bar:subject>blablabla</bar:subject> <dc:author xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" >blablabla</dc:author> </bar:excerpt> <!-- end copied excerpt --> </bla:container> _________________________________________________________________ Express yourself instantly with MSN Messenger! Download today - it's FREE! http://messenger.msn.click-url.com/go/onm00200471ave/direct/01/
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