[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: for-each loop in node set variable gives error
Your variable $employeeList is a result tree fragment and XSLT 1.0 does not allow you to use an RTF in a path expression. You need the xx:node-set() extension function, or an XSLT 2.0 processor, or an XSLT 1.0 processor that relaxes this rule. Michael Kay http://www.saxonica.com/ P.S. You might not be able to make sense of the error message, but there are many people on this list who can, and who would be able to answer your question more quickly if you quoted it. > -----Original Message----- > From: Ranjan K. Baisak [mailto:ranjanbaisak@xxxxxxxxx] > Sent: 02 September 2004 14:35 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: for-each loop in node set variable gives error > > Hello List, > My stylesheet contains following > declarations > > declaration 1: > <xsl:variable name="employeeList"> > <xsl:for-each select="//employee/*[name()!='max']"> > <xsl:if test="count(key('employee', @id))=0"> > <xsl:copy> > <xsl:copy-of > select="property[@name='cast']/@val"/> > <xsl:copy-of select="@name"/> > <xsl:copy-of > select="property[@name='language']"/> > </xsl:copy> > </xsl:if> > </xsl:for-each> > </xsl:variable> > > declaration 2: > <xsl:variable name="generatedEmployees"> > <xsl:for-each select="$employeeList/*"> > <xsl:sort select="@val"/> > <xsl:copy-of select="."/> > </xsl:for-each> > </xsl:variable> > > for-each loop for $employeeList/* in declaration 2 > gives error. I don't understand why it gives error. > Any clue? > > regards, > Ranjan > > > > _______________________________ > Do you Yahoo!? > Win 1 of 4,000 free domain names from Yahoo! Enter now. > http://promotions.yahoo.com/goldrush
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