[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Omit Data While Using Copy
How would I be able to display all of the data from the following xml file,
EXCEPT for the <titel> text? (see xml example below which is one of 1200)
<?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?> <kapitel><titel>Measures every 10 percussion hours</titel><text/><hanvisning from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapitel> I can use xsl:copy and select=node() to display everything, but no matter what I try, I can't seem to keep the <titel> from displaying. If I try to just use match, I am only able to display "Feeder". This is the basic xsl I was working from: <?xml version='1.0' encoding='utf-8' ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="kapitel/hanvisning"> <xsl:copy> <xsl:value-of select="node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> If you respond to this, please be fairly descriptive, as I am very new to xsl. Thanks in advance, Trevor _________________________________________________________________ Take charge with a pop-up guard built on patented Microsoft. SmartScreen Technology. http://join.msn.com/?pgmarket=en-ca&page=byoa/prem&xAPID=1994&DI=1034&SU=http://hotmail.com/enca&HL=Market_MSNIS_Taglines Start enjoying all the benefits of MSN. Premium right now and get the first two months FREE*.
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