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Re: Dynamic XPath expression (I know it doesnt work in

Subject: Re: Dynamic XPath expression (I know it doesnt work in XSLT1.0)
From: Josh Canfield <joshcanfield@xxxxxxxxx>
Date: Thu, 26 Aug 2004 10:50:27 -0700
dynamic xpath
"since it increases the parse time so much...."

I'm very surprised by this statement, do you have any data that
supports the statement? Specifically that the parse time is increased?

Doing any sort of dynamic compilation of xpath is going to increase
the run time of the transformation. Using the built-in evaluate
functions seems like it would be the most efficient solution...

Josh

On Thu, 26 Aug 2004 12:38:47 -0500, Matt Dittbenner
<mbditt@xxxxxxxxxxxxxxxxx> wrote:
> Hello,
> 
> After some pretty exhaustive searching on the web, I have decided to
> join the list. I have noticed in the archives that more than one person
> has had the same issue as I have...how to create an XPath expression
> dynamically (from a variable, etc). The answer to these questions was to
> use any of the available *:evaluate functions. I would like to try to
> avoid that, since it increases the parse time so much....and that is not
> acceptable.
> 
> My question is if there is any other way to accomplish this, for example
> using XSLT2.0. I have found little information about the newer XSLT
> recommendation, and the information I have found is fairly cryptic (at
> least to me). Here is a more detailed example of what I am trying to do:
> 
> ===================================
> doc.xml
> <tag2>Data I want...</tag2>
> 
> template.xhtml
> <p>
>    <getContent path="tag2/text()"/>
> </p>
> 
> stylesheet.xsl
> <xsl:variable name="path" select="/p/getContent/@path" />
> <xsl:value-of select="document('doc.xml')/$path"/>
> ===================================
> 
> In an ideal world, stylesheet.xsl would use the XPath expression from
> the attribute in template.xhtml to access another document (doc.xml) and
> then grab the data located there. How do I do this?!
> 
> Thanks in advance,
> Matt Dittbenner

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