[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: position() in xsl:for-each
> Ah. That explains everything. > > I think I'll copy the <object>s of the correct @type into another > tree, and then use this tree to output the table correctly. > > That is, if there's no simpler solution :) You can just get the following sibling that has the type1 type attribute: <xsl:apply-templates select="following-sibling::*[@type='type1'][1]"/> Best Regards, George ----------------------------------------------- George Cristian Bina <oXygen/> XML Editor & XSLT Editor/Debugger http://www.oxygenxml.com
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|