[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: This could be simple, but not for me!
The best way to approach this is to find out what you need to do logically. Based on your output, this is my though: Match every unique occurrence of Root/Community/A/B/Info/Detail/@no (use a template of a for-each) Concat the value of @no, Detail. Loop through all the matches of Detail and Detail/@no (most likely using a key, but you could use other means) Print the ancestor::City and the preceding-sibling::Name Of course, you didn't provide an actual spec, and this could be completely wrong given your rules. This ought to help you approach it though. With most programming, it is usually just a logical decomposition into functions. -----Original Message----- From: Kenny Bogoe (BogoeMD) [mailto:kenny@xxxxxxxxx] Sent: Tuesday, May 25, 2004 7:15 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: This could be simple, but not for me! Hi, Though I have been working sometime with XSLT, I am having trouble with this transformation. Anyone know how to do this? The XML source is from a database and is really really huge in size, so performance of the transformation is very critical... <Root> <Community> <City>City1</City> <A> <B> <Name>Name1</Name> <Info> <Detail no="100">Red</Detail> </Info> </B> <B> <Name>Name2</Name> <Info> <Detail no="200">Blue</Detail> </Info> </B> <B> <Name>Name3</Name> <Info> <Detail no="300">Green</Detail> </Info> </B> </A> </Community> <Community> <City>City2</City> <A> <B> <Name>Name4</Name> <Info> <Detail no="100">Red</Detail> </Info> </B> <B> <Name>Name5</Name> <Info> <Detail no="200">Blue</Detail> </Info> </B> <B> <Name>Name6</Name> <Info> <Detail no="400">Yellow</Detail> </Info> </B> </A> </Community> </Root> This is the result I need to produce: 100, Red City1 Name1 City2 Name4 200, Blue City1 Name2 City2 Name5 300, Green City1 Name3 400, Yellow City2 Name6
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