[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XSL-output for xml without parent node
I just read the post thoroughly and realized he said he is getting out if he only has one node. I'm sure that is the case. Check out something like w3schools.com or topxml.com for some decent tutorials and references. -----Original Message----- From: Josh Canfield [mailto:Josh.Canfield@xxxxxxxxxxxx] Sent: Tuesday, May 04, 2004 7:00 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: XSL-output for xml without parent node It can't be this easy, I'm sure you'd get an error if this was true, but you are wrapping your RESULT elements in a node, right? I tried your xsl with this xml: <root> <RESULT ID="1" NAME="te"/> <RESULT ID="2" NAME="tes"/> <RESULT ID="3" NAME="tess"/> </root> and got this result: <html> <body>123</body> </html> Josh -----Original Message----- From: Bret [mailto:laker_66@xxxxxxxxx] Sent: Tuesday, May 04, 2004 2:04 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: XSL-output for xml without parent node Hi! I have the following xml . <RESULT ID="1" NAME="te"/> <RESULT ID="2" NAME="tes"/> <RESULT ID="3" NAME="tess"/> I have the following xsl <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xml:space="preserve"> <xsl:template match="/"> <html> <body> <xsl:for-each select="//RESULT"> <xsl:value-of select="@ID"/> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> when i use the following xsl i'm not getting any output . I'm guessing it has to do with <xsl:for-each select="//RESULT"> . I do get output if i have only one record in the XML file . Any help appreciated . Thanks!!!! __________________________________ Do you Yahoo!? Win a $20,000 Career Makeover at Yahoo! HotJobs http://hotjobs.sweepstakes.yahoo.com/careermakeover
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