Is it possible to sort the way I want

I am building a flat table from the contents of a
hierarchical XML tree.  I want to sort on the fully
qualified name of the element but the data does not
have a qname attribute.  Is it possible?

For example the data might look like this (a
representation of Java code perhaps):
<package name="serviceb">
  <package name="subpackageofb">
  </pacakge>
  <package name="anothersubpackagetofb">
  </pacakge>
</pacakge>
<package name="servicea">
  <package name="subpackageofa">
    <package name="subsubpackageofa">
    </pacakge>
  </pacakge>
  <package name="anothersubpacakgeofa">
  </pacakge>
</pacakge>
<package name="servicec">
</pacakge>

and I want the flat list to look like this:
serviceA
serviceA.anothersubpackageofa
serviceA.subpackageofa
serviceA.subpackageofa.subsubpackageofa
serviceB
serivceB.anothersubpackageofa
serviceB.subpackageofa
serivceC

when I process this using:
<xsl:for-each select="//package">
  <xsl:sort select="@name"/>
    stuff to build the table...

I get this as my order
serviceA
serviceB
serivceC
serivceB.anothersubpackageofa
serviceA.anothersubpackageofa
serviceA.subpackageofa.subsubpackageofa
serviceB.subpackageofa
serviceA.subpackageofa

which is as expected since it is sorting on just the
name of the package.

I also tried this:
<xsl:for-each select="//package">
  <xsl:sort select="ancestor-or-self::*/@name"/>
but that seemed to give me document order or at least
not what I want.

Can this be done directly?  Can I derive the fully
qualified name using XPath for use in the select of
the sort element?  I have a template that outputs the
fully qualified name but it will not 'fit' in a select
statement.  Or am I forced to insert the qualified
name into the XML?

Any advice would be appricated.

Thanks,

IL

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