RE: xsl:if statement with numeric

Hallo Andreas

Thank you very much for your kind answer. 
That was a great idea and I like you're solution.  
have a nice day 

Tuan



> > -----Original Message-----
> > From: Tuan Luu [mailto:tuanluu@xxxxxx]
> >
> > somehow I  did find a solution:
> >
> 
> Hi,
> 
> Well, to add a few pointers :
> 
> > >
> > > <xsl:template match="monat">
> > >         <xsl:if test= "numeric(.) &lt; 100.00">
> 
> This should be number() instead of numeric(), but this you already
> discovered..
> 
> > >             <xsl:variable name="farbe">#00ff00</xsl:variable>
> > >         </xsl:if>
> > >     <td bgcolor="$farbe" align="right">
> 
> Then this here should become:
> 
> <td bgcolor="{$farbe}" align="right">
> 
> Notice the curly braces {} to force the processor to interpret '$farbe' as
> a
> variable name, or more generally as an XPath expression.
> 
> Somehow, I would consider putting a color-map somewhere in the source XML,
> the stylesheet or a separate XML, like:
> 
> <colormap>
>   <color min="0" color="#ff9600" />
>   <color min="98.70" color="#ff0000" />
>   <color min="100" color="#00ff00" />
> </colormap>
> 
> Then you could avoid all the xsl:choose / xsl:if logic by merely fetching
> the color value corresponding to the number value in question, like
> 
> <xsl:template match="monat">
>   <td bgcolor="{/colormap/color[@min &gt;= number(current())][1]/@color}"
>       align="right">
> ...
> 
> So, fetch the color attribute from the first color node whose min value is
> greater than or equal to the current value.
> 
> 
> Hope this helps!
> 
> Cheers,
> 
> Andreas
> 

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