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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] replacing a node value identified by a variable
 I want to replace certain node values in elements that will be identified by an id passed as an parameter. I know I can not use a variable in a match, so I try to use apply-templates with select and mode. The pattern seems to be ok, the first example is doing well except I can not pass a variable. Using an apply-templates replaces ALL titles - and using apply-templates with a mode just copies the file... Any ideas? Your help is appreciated. This is working, but I can't pass the parameter: <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:template> <xsl:template match="/newspage/news[@id='1']/title"> <title>replace title</title> </xsl:template> This is supposed to work, but it replaces ALL titles... <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:template> <xsl:apply-templates select="/newspage/news[@id='1']/title"/> <xsl:template match="title"> <title>replace title</title> </xsl:template> Just copies file: <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:template> <xsl:apply-templates select="/newspage/news[@id='1']/title" mode="replace" /> <xsl:template match="title" mode="replace"> <title>replace title</title> </xsl:template> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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