RE: The pipe '|' operator: Does it mean Or or Union?

That makes sense, especially with the fact the 'or' returns a Boolean.
The color commentary is welcomed. :)

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Wendell Piez
Sent: Wednesday, January 14, 2004 1:12 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  The pipe '|' operator: Does it mean Or or Union?

At 12:15 PM 1/14/2004, Jeff wrote:
>kakridge@xxxxxxxxxxxxx wrote:
>>I've noticed the the Muenchian method uses '|' and that everyone
refers
>>to this as a Union.  However, I also read that this
>><xsl:template match="foo | foobar">
>>means to match the foo OR foobar elements.  Does the definition of the
>>operator change based on the application?
>
>Matching "foo | foobar" gives you the union of the set of all foo with
the 
>set of all foobar.  You can read it as "OR", but it's still a union 
>operator.  XPath has a separate "or" operator, but that's not the same
thing.

It may also help to recall the rationale for matching: my node matches a

pattern if there is another node in the document from which my node can
be 
retrieved, using the given pattern as an XPath expression. (This would
make 
for chaos, except of course not all XPath location paths are allowed as 
patterns -- only some of the ones that look "down").

Since all foo and all foobar elements have parent nodes, any of them can
be 
reached, from somewhere, using the XPath "foo | foobar". In other words,

the pattern matches any node in the union set of foo and foobar
elements.

(The "or" operator returns a Boolean, so it can't be used in a pattern
-- 
apart from inside predicates -- since it doesn't return nodes at all.)

Hm, I seem to be offering lots of color commentary today....

Cheers,
Wendell


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