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hello all,
I'm trying to 'xsl:number' some sorted multileveled nodes. According to some messages I found in the archive of this mailing list, I should first put my sorted node-set into a xsl:variable. (Otherwise numbering will take place according to the order of nodes in the xml document!). To reproduce my struggle: a) xml input: <thing sequenceIndex="30" key="hardware"> <thing sequenceIndex="20" key="computerB"> </thing> <thing sequenceIndex="5" key="computerA"> <thing sequenceIndex="5" key="diskOne"> </thing> <thing sequenceIndex="10" key="diskTwo"> </thing> </thing> <thing <thing sequenceIndex="10" key="software"> </thing> b) wished output: (sorted on attribute 'sequenceIndex') 1 software 2 hardware 2.1 computerA 2.1.1 diskOne 2.1.2 diskTwo 2.2 computerB c) xsl <xsl:variable name="sorted-things" select="//Thing"> <!-- see question 1 below --> </xsl:variable> <xsl:for-each select="$sorted-things"> <fo:block> <xsl:number level="multiple" grouping-size="1" grouping-separator="."/> <xsl:text> </xsl:text> <xsl:value-of select="@key"/> </fo:block> </xsl:for-each> Question 1: how to put sorted nodes into the variable ($sorted-things)? Sortation according to <xsl:sort select="@sequenceIndex" data-type="number" order="ascending"/>. Question 2: is this "use a variable"-strategy correct to xsl:number a set of nodes according to their sortation (and not their xml document order)? any help appreciated, Mathieu van Echtelt Groningen the Netherlands _________________________________________________________________ MSN Zoeken helpt je om de gekste dingen te vinden! http://search.msn.nl XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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