[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Re for-each identifying current iteration
Mark Williams wrote:
Hi,Hello I think position() could do the job: #xsl <xsl:template match="/"> <xsl:for-each select="/root/node"> <xsl:value-of select="position()"/> </xsl:for-each> </xsl:template> # xml-file <root> <node/> <node/> </root> Regards ThomasRasmussen XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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