[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: How to unflatten the source XML ?
Hi, > Would you please tell me how to group fixed number (say 3) of > consecutive node together? <xsl:template match="*[item]"> <xsl:for-each select="item[position() mod 3 = 1]"> <group id="{position()}"> <xsl:copy-of select=". | following-sibling::item[position() < 3]"/> </group> </xsl:for-each> </xsl:template> Cheers, Jarno - Project Pitchfork: Carrion XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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