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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Problems doing XSL Transformation using ASP
 The XSL file you posted, when applied to the XML,
_works fine with MSXML3.0_ . From your code, it looks
to me that you are using MSXML2.0 . MSXML2.0 does not
conform to the official W3C XSL Recommendation. I
guess MSXML2.0 supports the _W3C XSL Working Draft_ .
But _MSXML3.0 supports W3C XSLT 1.0 and the W3C XPath
1.0 Recommendations_. If you can try with MSXML3.0, I
think the problem will be solved. Or you can try with
MSXML4.0. It also supports W3C Recommendations..
Regards,
Mukul
--- Rangarajan Calyanakoti <crranga@xxxxxxxxxxx>
wrote:
> Folks,
>
> I have a very simple XML, XSL file and a very simple
> ASP file to perform the
> XSL Transformation on the XML file using the XSL
> file and providing it to
> any client browswer. I get the following error.
>
> NOTE: If I open the xml file (that is just from the
> client side) it works
> just fine!
>
> What am I missing???
>
> ERROR
> ---------
>
> msxml3.dll error '80004005'
>
> The stylesheet does not contain a document element.
> The stylesheet may be
> empty, or it may not be a well-formed XML document.
>
> /test/vqtreport.asp, line 9
>
>
> ASP FILE - dummy.asp
> ------------
> <%@ language=javascript %>
> <%
> var xslt = new
> ActiveXObject("Msxml2.XSLTemplate");
> var xslDoc = new
> ActiveXObject("Msxml2.FreeThreadedDOMDocument");
> var xslProc;
> xslDoc.async = false;
> xslDoc.resolveExternals = false;
> xslDoc.load("dummy.xsl");
> xslt.stylesheet = xslDoc;
> var xmlDoc = new
> ActiveXObject("Msxml2.DOMDocument");
> xmlDoc.async = false;
> xmlDoc.resolveExternals = false;
> xmlDoc.load("dummy.xml");
> xslProc = xslt.createProcessor();
> xslProc.input = xmlDoc;
> xslProc.transform();
> Response.Write(xslProc.output)
> %>
>
>
> XML FILE - dummy.xml
> ------------
> <?xml version="1.0"?>
> <?xml-stylesheet type="text/xsl" href="dummy.xsl"?>
>
> <DUMMY>
> </DUMMY>
>
> XSL FILE - dummy.xsl
> ------------
> <?xml version='1.0'?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="html" indent="yes"/>
>
> <xsl:template match="/">
> <html>
> <h1>Yahoooooooo</h1>
> </html>
> </xsl:template>
> </xsl:stylesheet>
>
>
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