Re: generate XHTML header without causing xmlns attrib

Hi Jarkko,

I thought I had to declare the name space in the xsl:template line like this:

<xsl:template name="exparameters" match="EX_PARAMETERS"

xml:space="preserve" xmlns="http://www.w3.org/1999/xhtml" xmlns:fo="http://www.w3.org/1999/XSL/Format">

<table border="1" cellpadding="3" cellspacing="0"

class="parameters" >

   <thead>
     <tr>
       ...

Well, normally these kind of declarations are done in the stylesheet level.

Originally I did it the way you suggests:
I have removed the xml namespace declaration in the template def. and tried this:

<xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

However I get that xmlns="" in my table anyway?

The funny part is, I have two <table> tags in the page which is generated, and it is only in the second one that gets the xmlns attribute - why is that?

The template declarations look like this (now):
<xsl:template name="query" match="QUERY">
And <xsl:template name="exparameters" match="EX_PARAMETERS" xml:space="preserve">

First table tag in generated xhtml looks like this
<table class="querydef" cellspacing="0" cellpadding="3" border="1">

Second table tag looks like this
<table xmlns="" class="parameters" cellspacing="0" cellpadding="3" border="1">

I have tried searching the web for answers, but I don't think I've used the right keywords - I haven't been able to find anything which could lead me towards a solution to this. I am a beginner, so it might be even the simplest thing I've missed - so any help will be appreciated.

Have a great weekend everyone,
Flemming

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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