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Hi, Can anyone help me over this problem i had with a stylesheet. suppose i have an xml like this: <xml> <path> <f> <i>1</i><t>1</t> </f> <f> <i>2</i><t>2</t> </f> <f> <i>3</i><t>3</t> </f> </path> <path> <f> <i>1</i><t>2</t> </f> <f> <i>2</i><t>1</t> </f> </path> <path> <f> <i>1</i><t>4</t> </f> <f> <i>3</i><t>3</t> </f> <f> <i>4</i><t>2</t> </f> </path> </xml> what i want to find is a path node that contain i= 1 and t = 1 where i and t is in the same node (i.e. in the same f node) so the result i want from the above xml is: <xml> <path> <f> <i>1</i><t>1</t> </f> <f> <i>2</i><t>2</t> </f> <f> <i>3</i><t>3</t> </f> </path> </xml> and i was wondering, is it possible to get the above with ONE query statement? something like this: ex. 1 <xsl:template match="xml"> <xml> <xsl:copy-of select="path[f/i = '1' and f/t = '1']"/> </xml> </xsl:template> obviously this doesn't work as this query will copy the first two path nodes. i know this will work if i go down to the bottom level and do something like this: ex. 2 <xsl:template match="xml"> <xsl:for-each select="path"> <xsl:for-each select ="f[i='1' and t='1']"> <xsl:copy-of select="../."/> </xsl:for-each> </xsl:for-each> </xsl:template> but i want to get the correct results without going down to the bottom level, so i was wondering, whether it is possible to query the node at the xml level (like ex. 1) i hope this is not confusing and i really appreicate your time. Thanks in advance regards Kit _________________________________________________________________ ¨Ï¥Î MSN Messenger¡A»PªB¤Í¦b½u¤W²á¤Ñ: http://messenger.microsoft.com/tc XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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