XSLT Sort - returning attributes

PLAT: WIN2K
MSXML2.Domdocument40
using 'transformNodeToObject'
Hi, very simply Im trying to do a plain sort on my XML Doc.
I want to return the XML doc in exactly the same format that it was input
into, simply sorted.

Using Microsoft's MSDN example:
XML FILE
<?xml version="1.0"?> 
<COLLECTION dateCreated="01-04-2000"> 
<BOOK PK="2" > 
	<TITLE>Splish Splash</TITLE> 
	<AUTHOR>Paula Thurman</AUTHOR> 
	<PUBLISHER>Scootney</PUBLISHER> 
</BOOK> 
<BOOK PK="1" > 
	<TITLE>Splish Splash</TITLE> 
	<AUTHOR>Paula Thurman</AUTHOR> 
	<PUBLISHER>Scootney</PUBLISHER> 
</BOOK> 
</COLLECTION>
XSL STYLESHEET
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/">
   <PriceList>
      <xsl:for-each select="COLLECTION/BOOK">
   <xsl:sort select="@PK" data-type="number"/>
   <xsl:copy>
   <xsl:apply-templates select="*"/>
   <xsl:apply-templates select="@*"/> [my inserted line]
   </xsl:copy>
      </xsl:for-each>
   </PriceList>
  </xsl:template>

  <xsl:template match="*">
   <xsl:copy>
   <xsl:apply-templates />
   </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

END

Basically from the above example, " <xsl:apply-templates select="*"/> " will
return me all the elements of the book node, however I also want to retrieve
all attributes.
I 've tried  "   <xsl:apply-templates select="@*"/>  " to get all
attributes, but obviously Im doing something wrong.
Is there any simpler way of  going about sorting an xml doc and returning
the entire document in XML format (only sorted) ?

thanks
Karlo Swart










 


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