RE: Vertical table display with sort

<snip>
<xsl:for-each select="o/com/hereyougo/*">
</snip>

You can't explicitly say the element name
hereyougo is the element name. If you go thro the
xml file, it can be different element for the next pair.


<?xml version="1.0"?>
<o>
	<com>
		<hereyougo>
			<first displayposition="4"
displayname="raman4">4</first>
			<second displayposition="1"
displayname="raman1">1</second>
			<third displayposition="3"
displayname="raman3">3</third>		
			<fourth displayposition="2"
displayname="raman2">2</fourth>
		</hereyougo>
		<imaycome>
			<four displayposition="4"
displayname="raman4">22</four>
			<five displayposition="1"
displayname="raman1">33</five>
			<six displayposition="3"
displayname="raman3">44</six>			
			<firvi displayposition="2"
displayname="raman2">11</firvi>			
		</imaycome>
	</com>
</o>


is the xml file.

-----Original Message-----
From: Zink, Juergen [mailto:Juergen.Zink@xxxxxxxxxxxxxxxxxxxx]
Sent: Wednesday, April 30, 2003 2:40 PM
To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
Subject: AW:  Vertical table display with sort
Importance: Low


Hi,

<snip>
I would like to sort the following XML file based on the displayposition.
I am printing the value and displayname. 
<snip>

another solution is grouping with key.

  <!-- grouping with the same displayposition -->
  <xsl:key name="displayposition" match="*[@displayposition]"
use="@displayposition"/>

  <xsl:template match="/">
    <table>
      <!-- get all possible keyvalues in sorted order -->
      <xsl:for-each select="o/com/hereyougo/*">
        <xsl:sort select="@displayposition"/>
        <tr>
          <th><xsl:value-of select="@displayname"/></th>
          <!-- now process all elements with the same key -->
          <xsl:for-each select="key('displayposition', @displayposition)" >
            <td><xsl:value-of select="." /></td>
          </xsl:for-each>
        </tr>
      </xsl:for-each>
    </table>
  </xsl:template>

Cheers,

Juergen


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