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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Parameterized sort
 For example, here is my XML:
<document>
<row><column name="FirstName">John</column>
<column name="LastName">Doo</column>
</row>
<row><column name="FirstName">Alice</column>
<column name="LastName">Mulcaster</column>
</row>I want to sort the list by either FirstName or LastName. Here is my xsl file: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:xalan="http://xml.apache.org/xalan"> <xsl:output method="xml"/> <xsl:param name="sortByColumn" select="'FirstName'"/> <xsl:template match="/"> <Document> <xsl:for-each select="Document/row"> <xsl:sort select="column[@name=*[name()=$sortByColumn]]"/> <row> <xsl:apply-templates select="column"/> </row> </xsl:for-each> </Document> </xsl:template> <xsl:template match="column"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet> However, it still doesn't work. I know that the sort key if defined as parameter, I should use "xalan:evalue($sortKey)" or "*[name() = $sortKey]". In this case, I want to sort the rows by the FirstName column or by LastName column and First Name. If I say, <xsl:sort select="column[@name='FirstName']"/> then, it works properly. Many thanks in advance. _________________________________________________________________ Add photos to your messages with MSN 8. Get 2 months FREE*. http://join.msn.com/?page=features/featuredemail XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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