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RE: Variable select="concat()" not loading variable.

Subject: RE: Variable select="concat()" not loading variable.
From: Jarno.Elovirta@xxxxxxxxx
Date: Thu, 24 Apr 2003 11:45:11 +0300
xsl value of select concat
Hi,

> I am trying to concatinate a collection of text() strings 
> (see xsl below)
> however the variable (timestamps)  is not being filled with 
> any data.  Could
> someone tell me why?  The total number of timestamps to be 
> concatinated is
> 10,000.
> 
> Kind regards
> 
> Simon
> 
> 
> [code]
> <!--
> <xsl:for-each select="ROW/TIMESTAMP">
>     <xsl:if test="position() = 1">
>         <xsl:element name="starttime"><xsl:value-of select="."
> /></xsl:element>
>     </xsl:if>
>     <xsl:if test="position() = last()">
>         <xsl:element name="endtime"><xsl:value-of select="."
> /></xsl:element>
>     </xsl:if>
> 
>     <xsl:variable name="timestamps" 
> select="concat($timestamps, ./text())"
> />
> 
>     <xsl:if test="position() != last()">
>         <xsl:variable name="timestamps" 
> select="concat($timestamps, $delim)"
> />

XSLT variables cannot be updated--search the list archives for gizillion answers on why not. You want something like

<xsl:variable name="x" select="ROW/TIMESTAMP" />
<starttime>
  <xsl:value-of select="$x[1]" />
</starttime>
<endtime>
  <xsl:value-of select="$x[position() = last()]" />
</endtime>
<xsl:variable name="timestamps">
  <xsl:for-each select="$x">
    <xsl:if test="not(position() = 1)">
      <xsl:value-of select="$delim" />
    </xsl:if>
    <xsl:value-of select="text()" />
  </xsl:for-each> 
</xsl:variable>

Cheers,

Jarno - Assemblage 23: Disappoint (Funker Vogt Remix)


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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