<xsl:when test="position()%2=0">

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Subject: <xsl:when test="position()%2=0">
From: "Luke Ambrogio" <gryzlaw@xxxxxxxxxxx>
Date: Mon, 21 Apr 2003 17:09:18 +0200 (W. Europe Daylight Time)

first of all i wish to thank all of you guys (and gals) for providing me with great help. now i have another query

i would like to find the position of a node whether it is odd or even, and tried to use position() mod 2, but i don't know how to do it

can anyone tell me how to find the remainder of a division or else any ideas on how to find whether a node is odd or even

10x, regards

luke

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Current Thread
<xsl:when test="position()%2=0"> Luke Ambrogio - Mon, 21 Apr 2003 11:05:23 -0400 (EDT) <= Andrew Watt - Mon, 21 Apr 2003 11:51:56 -0400 (EDT) <Possible follow-ups> Craig Kattner - Mon, 21 Apr 2003 11:32:06 -0400 (EDT)

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Re: XSL-List Digest V4 #1252, Joseph Kesselman	Thread	Re: <xsl:when test="position(, Andrew Watt
RE: A Question TO XSLT Ne, Boris Kortiak	Date	RE: <xsl:when test="position(, Craig Kattner
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