[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: generate full xpath name to an attribute?
At 04:23 PM 3/31/03 +0100, you wrote:
yikes! - looks like the simplest way is to have: i ended up using a name= on the above and doing a call-template. depending on your document type this might not give you an unambigous path back to your attribute right. i have arrays, so that is another problem :( (and you probably want a @ before that last step) yes and tried doing that with if's. i found some stuff in the archives about determining whether something is an element or an attribute at http://www.biglist.com/lists/xsl-list/archives/200212/msg00523.html and http://www.biglist.com/lists/xsl-list/archives/200212/msg00518.html <xsl:if test="../@*/."> <xsl:if test="../@*"> count(. | ../@*) = count(../@*) none of these seem to work very well. they tend to generate stuff like: input/Nodes@Node/Point/3.14159265358979 using the first two: <xsl:if test="../@*/."> <xsl:text>@</xsl:text> </xsl:if> <xsl:if test="not(../@*/.)"> <xsl:text>/</xsl:text> </xsl:if> does this: input/Nodes@Node/Point/3.14159265358979 the @ is in the wrong place and the value (pi) instead of the name is coming out. what i want is input/Nodes/Node/Point/x (i will solve the subscript problem later with number or something i hope). seems like there should be an easier way to skin this cat :(. thanks
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