[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Re: Can one _generate_ namespace nodes?
"Joseph Kesselman" <keshlam@xxxxxxxxxx> wrote in message news:OF61D39BC9.77924166-ON85256CD7.00611483-85256CD7.0062E761@xxxxxxxxxxxxx > Yes, generating the <xsl:stylesheet> explicitly as <newxsl:stylesheet> > rather than using <xsl:copy> would result in newxsl: being declared at the > root. > > But then any elements -- or XPaths -- copied from the source stylesheet > would have the reverse problem; they'd still be using the xsl: prefix and > would need to declare *that* prefix. What about the following: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:newxsl="http://dymmy/Transform" > <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:namespace-alias stylesheet-prefix="newxsl" result-prefix="xsl"/> <xsl:template match="/"> <newxsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <newxsl:text>foo</newxsl:text> </newxsl:stylesheet> </xsl:template> </xsl:stylesheet> The "newxsl" prefix will be bound to the XSLT namespace and the serializer will generate the necessary namespace definition. In addition to this, a definition of the XSLT namespace bound to the prefix "xsl" is also present in the newxsl:stylesheet. The result will be: <newxsl:stylesheet xmlns:newxsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <newxsl:text>foo</newxsl:text> </newxsl:stylesheet> Therefore, any XPath expressions containing the "xsl" prefix will be evaluated correctly. In the same way, any other necessary prefixes can be specified on the newxsl:stylesheet element. Is there an example, which is still problematic? ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|