default namespace in match attribute of xsl:template

Hello XSL-list,

We have an XML that looks like this:

<soap:Envelope xmlns:soap='http://schemas.xmlsoap.org/soap/envelope'>
<soap:Boby>
<reponse xmlns='someuri'>
    <files>
    <files>
</response>
</soap:Body>
</soap:Envelope>

the XSL looks like this:

<xsl:template match='/'>
<xsl:apply-templates select='Envelope'/>
</xsl:template>

<xsl:template match='soap:Envelope'>
<xsl:message>soap:Envelope</xsl:message>
<xsl:apply-templates select='Body'/>
</xsl:template>

<xsl:template match='soap:Body'>
<xsl:message>soap:Body</xsl:message>
<xsl:apply-templates select='response'/>
</xsl:template>

<xsl:template match='response'>
<xsl:message>response</xsl:message>
</xsl:template>

The response element falls in the default namespace 'someuri'. How do you
indicate this namespace in the match parameter of xsl:template. We tried
match='response', match=':response', match='namespace::/response',
match='#default:response'.

By the way, we are using Xalan++ 1.4 as the processor. XML is parsed by
Xerces++ 2.1.

Is there a right way to do this?

With kind regards,
Peter Paulus

Neroc Publishing Solutions b.v.
De Run 1131
5503 LB VELDHOVEN
The Netherlands
tel: +31-40-2586666
fax: +31-40-2541893






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