[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: combining two variables to generate XPATH
Hi bix, I think everyone is getting caught up in your explicit question :) and not understanding what you want, or perhaps I am missing something... Based on previous examples: concat($node,'/',$type,'/item') -- assuming $type is the name of an element select="'someBranch'" -- assuming 'someBranch' is the name of an element this is very simple to solve in XSLT 1.0, as I posted earlier: <xsl:template name="foo"> <xsl:param name="node"/> <xsl:param name="branch" select="'someBranch'"/> <xsl:for-each select="$node/*[name()=$branch]/leaf"> <xsl:value-of select="@id" /> </xsl:for-each> </xsl:template> best, -Rob > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Michael Kay > Sent: Tuesday, December 17, 2002 1:55 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: combining two variables to generate XPATH > > > > Is that FAQ outdated?? I know that the following code works > > just fine: > > > > <xsl:template match="proc"> > > <xsl:call-template name="foo"> > > <xsl:with-param name="node" select="." /> > > </xsl:call-template> > > </xsl:template> > > > > <xsl:template name="foo"> > > <xsl:param name="node"/> > > <xsl:for-each select="$node/branch/leaf"> > > <xsl:value-of select="@id" /> > > </xsl:for-each> > > </xsl:template> > > > > What is different about a path with a single variable, and a > > path with two > > variables? Why can't I specify a second variable: > > > > <xsl:template name="foo"> > > <xsl:param name="node"/> > > <xsl:param name="branch" select="'someBranch'"/> > > <xsl:for-each select="$node/$branch/leaf"> > > <xsl:value-of select="@id" /> > > </xsl:for-each> > > </xsl:template> > > > > The first step in a path expression can be any expression that returns a > node-set. The value of $node is a node-set. In XPath 2.0, subsequent > steps can also be expressions that return a node-set. But they can't be > expressions that return strings: the value of $branch is not a node-set, > it is a string. > > XPath variables represent values, they aren't macros that represent > parts of an expression. > > Michael Kay > Software AG > home: Michael.H.Kay@xxxxxxxxxxxx > work: Michael.Kay@xxxxxxxxxxxxxx > > > > > > >From: Mark Wilgus <mwilgus@xxxxxxxxx> > > > > > >I believe this is not possible. XSLT doesn't allow you > > >to use a variable for an XPath expression. See number 2 at the > > >following list: > > > > > >http://www.dpawson.co.uk/xsl/sect2/nono.html > > > > > > > -----Original Message----- > > > > From: bix xslt [mailto:bix_xslt@xxxxxxxxxxx] > > > > > > > <xsl:variable name="branch" > > > > >select="concat($node,'/',$type,'/item')" /> > > > > > <xsl:value-of select="$branch" /> > > > > ><!-- <xsl:for-each select="$branch"> > > > > > > > > > > > > _________________________________________________________________ > > Protect your PC - get McAfee.com VirusScan Online > > http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963 > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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