RE: xsl:attribute problem

You will need a named template, such as 

  <xsl:template name="php">
    <xsl:param name="value" select="'no param set'"/>
    <xsl:text disable-output-escaping="yes">&lt;?</xsl:text>
    <xsl:value-of select="$value"/>
    <xsl:text disable-output-escaping="yes">?&gt;</xsl:text>
  </xsl:template>

and then call the template using 

  <xsl:call-template name="php">
    <xsl:with-param name="value" select="something"/>
  </xsl:call-template>

whenever you want to output <? param text ?> etc...

cheers
andrew


> -----Original Message-----
> From: Jens Laufer [mailto:jens@xxxxxxxxxxxxxx]
> Sent: 02 December 2002 10:58
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  xsl:attribute problem
> 
> 
> Hi all,
> I need to solve this problem:
> I want to create this output from a XML-source and a XSL-stylesheet:
> 
> 
> <---snippet---!>
> <a href="mailto: <?php echo $email?>"><?php echo $email?></a>
> <---snippet---!>
> 
> 
> I am using this XSL-stylesheet:
> <---snippet---!>
> <?xml version="1.0" encoding="iso-8859-1"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> version="1.0">
> 
> 
>   <xsl:output method="html" indent="yes"/>
> 
> 
>   <xsl:template match="/document">
>      <a>
>       <xsl:attribute name="href">mailto:<xsl:apply-templates 
> select="email"/></xsl:attribute>
>       <xsl:apply-templates select="email"/>
>      </a>
>   </xsl:template>
> 
> 
>  <xsl:template match='email'>
>   <xsl:apply-templates/>
>  </xsl:template>
> 
> 
>  <xsl:template match='*|@*'>
>     <xsl:copy>
>         <xsl:apply-templates select='node()|@*'/>
>     </xsl:copy>
>  </xsl:template>
> 
> 
> </xsl:stylesheet>
> <---snippet---!>
> 
> 
> I tried this XML to get that output:
> ======================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><xsl:pi value="php">echo $email</xsl:pi></email>
> </document>
> 
> 
> 
> I get this error:
> java.io.IOException: /home/jens/test/test.xsl:7: element 
> `xsl:pi' is not 
> allowed inside attribute `href'.
> 
> 
> ================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><script language="php">echo $email</script></email>
> </document>
> 
> 
> I get this error:
> java.io.IOException: /home/jens/test/test.xsl:7: element 
> `script' is not 
> allowed inside attribute `href'.
> 
> 
> =================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><?php echo $email ?></email>
> </document>
> 
> 
> I get this output:
> 
> 
> <a href="mailto:";></a>
> 
> 
> =================================================================
> XML:
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email>&lt;?php echo $email ?&lt;</email>
> 
> 
> I get this output:
> 
> 
> <a href="mailto:<?php echo $email ?&lt;">&lt;?php echo $email 
> ?&lt;</a>
> ==================================================================
> I don't really know how to solve that and I am struggling 
> around with it since  
> a while now...
> 
> 
> Actually I don't want to change the stylesheet too much, 
> because with the 
> current stylesheet it should be possible to swap quickly technologies:
> You just change e.g. <?php echo $test?> into <%=test%> and 
> you can use jsp...
> So there should be no "technologiy" infromation in the stylesheet.
> 
> 
> I think especially the attributes are making a lot of problems...
> Any ideas?
> Thanks in advance!
> Jens
> 
> 
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list