RE: transforming xml to xhtml

Specifying the DTD in <xsl:output> merely declares your intent to
produce valid XHTML. Whether or not the XHTML is actually valid depends
entirely on your stylesheet. If your code is producing invalid XHTML,
then you need to work out what's wrong with the XHTML (from the error
messages produced when it's validated) and correct the relevant parts of
your stylesheet.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of True Name
> Sent: 10 December 2002 13:02
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  transforming xml to xhtml
> 
> 
> hello, i would like to use xsl transforming xml file to xhtml file
> 
> xsl like:
> 
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> 
> 
> <xsl:output method="xml" doctype-public="-//W3C//DTD XHTML 
> 1.0 Strict//EN"
> 				
> doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
> 				indent="yes"
> 				omit-xml-declaration="yes" />
> 
> ....
> 
> but every time i cannot get a valid xhtml file, would you 
> please tell me how 
> to transform xml to xhtml??
> 
> thanks in advance
> 
> 
> _________________________________________________________________
> MSN 8 with e-mail virus protection service: 2 months FREE* 
> http://join.msn.com/?page=features/virus
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list