Re: xslt replace special characters

thanks
al

From: Greg Faron <gfaron@xxxxxxxxxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  xslt replace special characters
Date: Fri, 08 Nov 2002 12:51:21 -0700

At 12:40 PM 11/8/2002, you wrote:

How do you replace characters in xslt.

i have a url string that may contain '?' , '&', and '='
i want to convert

? to %3f
= to %3d
& to %26

is there a good way to do this? i try using translate function but it doesn't work that well. i've also tried writing a recursive template that checks for all occurence of these characters and it doesnt seem to work.
any idea?

<xsl:template name="replace">
<xsl:param name="string" select="''"/>
<xsl:param name="pattern" select="''"/>
<xsl:param name="replacement" select="''"/>
<xsl:choose>
<xsl:when test="$pattern != '' and $string != '' and contains($string, $pattern)">
<xsl:value-of select="substring-before($string, $pattern)"/>
<!--
Use "xsl:copy-of" instead of "xsl:value-of" so that users
may substitute nodes as well as strings for $replacement.
-->
<xsl:copy-of select="$replacement"/>
<xsl:call-template name="replace">
<xsl:with-param name="string" select="substring-after($string, $pattern)"/>
<xsl:with-param name="pattern" select="$pattern"/>
<xsl:with-param name="replacement" select="$replacement"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

Greg Faron
Integre Technical Publishing Co.

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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