[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Delete XML Node
Deepak,
At 11:29 AM 11/1/2002, I wrote: Or more simply, if a Y will never have more than one B, you can do Of course the simpler solution to this (doh!) is: <xsl:template match="Y"> <xsl:if test="B[.='ABC'] or C[.='XYZ']"> <Y1> <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/> </Y1> </xsl:if> </xsl:template> or the analogous logic. Then you need no logic in the B template. Incidentally, this can be further compressed (if you like) as: <xsl:template match="Y[B[.='ABC'] or C[.='XYZ']]"> <Y1> <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/> </Y1> </xsl:template> <xsl:template match="Y"/> <!-- this suppresses a Y unless it matches the other template --> Cheers, Wendell
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