[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Selecting multi-existant elements only once
Your problem is to print unique nodes. You could do that the way you found out yourself or make use of keys , which is more efficient. Refer to the articles at Jeni's Page http://www.jenitennison.com/xslt/grouping/index.html HTH Vasu ----- Original Message ----- From: "Sorin Marti" <mas@xxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Monday, November 25, 2002 3:30 PM Subject: Re: Selecting multi-existant elements only once > I've got the solution...sorry for asking... > > <xsl:for-each select="//departement/profession[not(desc=preceding::desc)]"> > <xsl:value-of select="desc"/> > </xsl:for-each> > > Sorin Marti > > I wrote: > > > Hi all, > > > > I've got a XML-File with following structure. There are different > > departements and in each departement there are different professions. > > I want to have every profession of all departement once... If there is > > a Manager in departement a and departement b, "Manager" should only be > > printed out once... > > > > How can I do that? > > > > [...] > > <departement> > > <profession> > > <desc>Manager</desc> > > <salary>5000</salary> > > </profession> > > > > <profession> > > <desc>Assistant</desc> > > <salary>3000</salary> > > </profession> > > > > <profession> > > <desc>Employee</desc> > > <salary>2000</salary> > > </profession> > > </departement> > > > > <departement> > > <profession> > > <desc>Manager</desc> > > <salary>5000</salary> > > </profession> > > > > <profession> > > <desc>Worker</desc> > > <salary>2000</salary> > > </profession> > > </departement> > > > > [...] > > > > Thanks for your help ! > > > > Sorin > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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