Re: Outputting from more than one source

Joerg: It brings the same, even with this variable.
I'm using MSXML 4.0 (IE6) and Mozilla.
In both the result is the same.
Do you have another suggestion?

Liao: I could change the Java code to produce only one document.
But I don't want to change the specification of my project.
Just for the record, this project is a parcial requisite for my graduation.
Let's say I'll change my Jave code as a last option.


----- Original Message -----
From: "Joerg Heinicke" <joerg.heinicke@xxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Sunday, October 13, 2002 7:39 AM
Subject: Re:  Outputting from more than one source


> Hmm, it should work - at least it looks ok. What processor are you
> using? What happens if you do it in the following way:
>
> <xsl:variable name="reg" select="/clients_ora/reg |
>               document('other.xml')/clients_sqlsrv/reg |
>               document('another.xml')/clients_db2/reg"/>
>
> <xsl:apply-templates select="$reg">
>      <xsl:sort select="name"/>
> </xsl:apply-templates>
>
> Regards,
>
> Joerg
>
> Gustavo Moreira wrote:
> > Yes, but what if there are three or more documents?
> >
> > This, for instance, would this work?:
> >
> > xsl:apply-templates select="/clients_ora/reg |
> >   document('other.xml')/clients_sqlsrv/reg |
> >   document('another.xml')/clients_db2/reg">
> >       <xsl:sort select="name"/>
> >  </xsl:apply-templates>
> >
> > I am using this:
> >
> >       <xsl:apply-templates
> >          select="document('clients_sqlsrv.xml')//clients_sqlsrv/reg |
> >                  document('clients_ora.xml')//clients_ora/reg">
> >         <xsl:sort select="name"/>
> >       </xsl:apply-templates>
> >
> > ...and it doesn't work because it brings first all the clients from the
1st
> > file (ordered), then it follows with all the clients from the 2nd file
> > (ordered).
> > What I want is all clients from all files ordered, no matter what file
they
> > come from.
> >
> >
> > Gustavo Moreira
>
>
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>


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