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Re: Alternating Odd and Even with a twist
Subject: Re: Alternating Odd and Even with a twist
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 18 Oct 2002 16:44:55 +0200
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Instead of
<xsl:for-each select="*[substring(name(),1,4)='item']">
you can use then
<xsl:for-each select="*">
Regards,
Joerg
Kuhns Matt wrote:
Kuhns Matt wrote:
I want to alternate rows between a odd and even
class
in my CSS. The twist is that If there is no
information in the tag I don't want to print and I
want to maintain my odd and even structure. The html
would look like this
<class="rowodd">Hi</class>
<class="roweven">How are you?</class>
<class="rowodd">Bye</class>
xml:
<item1>Hi</item1>
<item2>How are you?</item2>
<item3>Bye</item3>
but say there was no information where How are you?
I want it to go:
<class="rowodd">Hi</class>
<class="roweven">Bye</class>
xml:
<item1>Hi</item1>
<item3>Bye</item3>
I can get the text not to print, but how do I assign
the classes?
I hope your elements are *not* named item1, item2,
item3...
But if you really want:
<xsl:for-each
select="*[substring(name(),1,4)='item']">
<class>
<xsl:choose>
<xsl:when test="position() mod 2 = 0">
<xsl:attribute
name="name">even</xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute
name="name">odd</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
<xsl:apply-templates/>
</class>
</xsl:for-each>
(Beware: untested)
I'm not sure what the "twist" is, it's a standard
technique.
J.Pietschmann
I'm sorry my description was a little misleading:
<System>
<Network>Hi</Network>
<Client>How are you?</Client>
<Server>Bye</Server>
<System>
So you couldn't parse the string and get the string
"item"
--
System Development
VIRBUS AG
Fon +49(0)341-979-7419
Fax +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de
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