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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xsl transforming xsl
 Hi List, I am trying to write an xsl which takes in an xsl template file as input, parses that file, and outputs an initial call-template node for use in building an xsl page for the application. So the template would be something like: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="link"> <xsl:param name="linkid"/> <xsl:param name="linkname"/> <xsl:param name="pagename"/> <xsl:param name="class"/> </xsl:template> </xsl:stylesheet> And I would like the output to be something like: <xsl:call-template name="link"> <xsl:with-param name="linkid"></xsl:with-param> <xsl:with-param name="linkname"></xsl:with-param> <xsl:with-param name="pagename"></xsl:with-param> <xsl:with-param name="class"></xsl:with-param> </xsl:call-template> Ok, heres the problem I am having: The xsl I am writing needs to reference the xsl namespace in order to properly access the xsl nodes within the template using XPath. But if I do not declare the xmlns:xsl="http://www.w3.org/1999/XSL/Transform", the XPath does not work. If I do declare the xmlns:xsl="http://www.w3.org/1999/XSL/Transform" then outputting the xsl:templates doesn't work because the processor tries to execute the xsl rather than just outputting it. I cannot output an arbitratry namespace for the xsl template which is generated and use namespace alias for mainly cosmetic reasons, but I think management will not bend on this. Does anyone have an idea of what might work in this situation? Is there a way to switch the namespace prefix as well as the definition of that namespace? Thanks, Alex _________________________________________________________________ Join the world?s largest e-mail service with MSN Hotmail. http://www.hotmail.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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